6x^2+x-1000=0

Solution for 6x^2+x-1000=0 equation:

6x^2+x-1000=0

a = 6; b = 1; c = -1000;
Δ = b2-4ac
Δ = 12-4·6·(-1000)
Δ = 24001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{24001}}{2*6}=\frac{-1-\sqrt{24001}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{24001}}{2*6}=\frac{-1+\sqrt{24001}}{12}
$